1/3y-1/4y=1/y^2

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Solution for 1/3y-1/4y=1/y^2 equation: 


D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

(1/3)*y-((1/4)*y) = 1/(y^2) // - 1/(y^2)

(1/3)*y-((1/4)*y)-(1/(y^2)) = 0

(1/3)*y+(-1/4)*y-y^-2 = 0

1/12*y-y^-2 = 0

y*(1/12-y^-3) = 0

-1*y^-3 = -1/12 // : -1

y^-3 = 1/12

-3 < 0

1/(y^3) = 1/12 // * y^3

1 = 1/12*y^3 // : 1/12

12 = y^3

y^3 = 12 // ^ 1/3

y = 12^(1/3)

y = 0

y = 0

y in { 0} 

y = 12^(1/3)

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